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"When I buy a widescreen TV, I shouldn't have to look at those black bars all the time!"
Well, for his birthday this April, I want to give him what he wants: Star Wars movies that fill up the entire screen without stretching. The zoom feature on our TV is Godawful, plus it cuts off the subtitles, so that's not a viable solution. Problem is, I'm not sure exactly how many pixels to crop off each side of the picture (I'm using Womble). I'm not going to pretend to know how many pixels are in a DVD image or which way they go, so try not to laugh when I give these figures. Corrections are expected and very welcome.
The resolution of an NTSC DVD (that's what I'm using) is 720x480. Since an anamorphic image is wider than it is tall, I assumed the 720 is horizontal resolution (again, please don't hit me). The Star Wars films were shot in a 2.39:1 aspect ratio (43:18 is a more exact figure). After some math, that means that a 16:9 TV is ~74.42% as wide as a theoretical 2.39:1 TV would be. So, I figured cropping off the offending black areas and then cropping off ~12.79% of the picture from the right and left. Since a 16:9 TV and the theoretical 2.39:1 TV would have the same height, the height minus the black bars on a 16:9 TV would hold the same size comparison to the height of the 2.39 TV that the width did (~74.42%). So the black bars take up ~12.79% from both the top and the bottom. So, that's 12.79% from all sides. If the width is 720 pixels, that's 92 pixels from the left and right, and 61 pixels from the top and bottom.
Okay, I screwed up, didn't I? Please enlighten me.