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Your age in Star Wars math

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Oh cool, this really worked!





Don't tell me your age; you probably would tell a falsehood anyway-


YOUR AGE BY STAR WARS MATHS

This is pretty neat.

DON'T CHEAT BY SCROLLING DOWN FIRST!
It takes less than a minute .
Work this out as you read ....
Be sure you don't read the bottom until you've worked it out!
This is not one of those waste of time things, it's fun.



1. First of all, pick the number of times a week that you would like to see a Star Wars movie
(more than once but less than 10)

























2. Multiply this number by 2 (just to be bold)





























3. Add 5































4. Multiply it by 50 -- I'll wait while you get the calculator





























5. If you have already had your birthday this year add 1755 .
If you haven't, add 1754.






























6. Now subtract the four digit year that you were born.














You should have a three digit number




























The first digit of this was your original number
(i.e., how many times you want to see a Star Wars movie each week).































The next two numbers are







YOUR AGE! (Oh YES, it is!!!!!)
THIS IS THE ONLY YEAR (2005) IT WILL EVER WORK, SO SPREAD IT AROUND WHILE IT LASTS.


tell me how you went!

OK, here is the proof. Spoilers for those who want the secret to remain a secret.








1. First of all, pick the number of times a week that you would like to see a Star Wars movie
(more than once but less than 10)

Let us call that number n

2. Multiply this number by 2 (just to be bold)

So, now we have 2n

3. Add 5

So, the total is now 2n + 5

4. Multiply it by 50 -- I'll wait while you get the calculator

Which equals 50 x (2n + 5) which simplifies to 100n + 250

5. If you have already had your birthday this year add 1755 .
If you haven't, add 1754.

Assume that in this late stage of the year, you have had your birthday, in which case, our sum becomes 100n + 250 + 1755 or 100n + 2005. If you haven't had your birthday, the sum becomes 100n + 2004

6. Now subtract the four digit year that you were born.

If we say that y is your year of birth, then the sum ends up being 100n + (2005 - y) or 100n + (2004 - y).

You should have a three digit number

Which is true, unless you are older than 100 years old.

The first digit of this was your original number
(i.e., how many times you want to see a Star Wars movie each week).

This is also true, since the first digit of a three-digit number is the number of hundreds. Since n was our initial number, and the first term in the equation is 100n this is therefore true.

The next two numbers are YOUR AGE!

If you've had your birthday this year, your age is this year (2005) minus the year you were born (y), i.e. 2005 - y. If not, your age is last year (2004) minus the year you were born (y), i.e. 2004 - y.

To form the three digit number, add the first term to the second term, i.e. 100n + (2005 - y). Lo and behold, that was our final sum at the end of stage 6.
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Yeah. I found it on the IMDb and thought it was cool, so I copied and pasted it here.
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Make sure you made the correct calculations and got the correct numbers in each step.
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yes it works, but it isn't difficult to work out someones age if they tell you the year the were born and if the've had their birthday this year.
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hmm funny, but yeah again its not hard to find someones age if they tell you the year they were born and if they have had there beday
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Shimraa has a point. And while "THIS IS THE ONLY YEAR IT WILL EVER WORK," next year, just at 1756 instead of 1755. Oooh.

Nice find, though, Adam. It's like magic math, but with a Star Wars reference thrown in.